1. Write the balanced chemical equation:

CH₄ + 4Cl₂ → CCl₄ + 4HCl

2. Calculate the molar mass of methane (CH₄):

* C: 12.01 g/mol

* H: 1.01 g/mol

* Molar mass of CH₄ = 12.01 + (4 * 1.01) = 16.05 g/mol

3. Calculate the moles of methane:

* Moles = mass / molar mass

* Moles of CH₄ = 8.00 g / 16.05 g/mol = 0.498 mol

4. Use the mole ratio from the balanced equation:

* The balanced equation shows a 1:1 mole ratio between CH₄ and CCl₄. This means for every 1 mole of CH₄ reacted, 1 mole of CCl₄ is produced.

5. Calculate the moles of CCl₄ formed:

* Moles of CCl₄ = 0.498 mol

6. Calculate the molar mass of CCl₄:

* C: 12.01 g/mol

* Cl: 35.45 g/mol

* Molar mass of CCl₄ = 12.01 + (4 * 35.45) = 153.81 g/mol

7. Calculate the mass of CCl₄ formed:

* Mass = moles * molar mass

* Mass of CCl₄ = 0.498 mol * 153.81 g/mol = 76.7 g

Therefore, 76.7 g of CCl₄ is formed by the reaction.