The reaction between lead acetate solution (Pb(CH₃COO)₂) and potassium iodide solution (KI) is a double displacement reaction that results in the formation of a bright yellow precipitate. Here's the balanced chemical equation:

Pb(CH₃COO)₂(aq) + 2KI(aq) → PbI₂(s) + 2KCH₃COO(aq)

Explanation:

* Lead acetate (Pb(CH₃COO)₂) and potassium iodide (KI) are both soluble ionic compounds, meaning they dissociate into their respective ions in solution.

* Lead ions (Pb²⁺) and iodide ions (I⁻) react to form lead iodide (PbI₂), a bright yellow solid that is insoluble in water. This is why it precipitates out of the solution.

* Potassium ions (K⁺) and acetate ions (CH₃COO⁻) remain in solution as potassium acetate (KCH₃COO), which is soluble in water.

Observations:

* When you mix the two solutions, a bright yellow precipitate will form immediately, indicating the formation of lead iodide.

* The reaction is exothermic, meaning it releases heat, and the solution might feel slightly warm.

Net Ionic Equation:

The net ionic equation focuses only on the species that participate in the formation of the precipitate:

Pb²⁺(aq) + 2I⁻(aq) → PbI₂(s)

This equation clearly shows the reaction between lead ions and iodide ions, leading to the formation of lead iodide precipitate.