1. Calculate the empirical formula mass:

* C: 12.01 g/mol

* H: 1.01 g/mol

* Empirical formula mass = (12.01) + (3 * 1.01) = 15.04 g/mol

2. Determine the whole number ratio between the molar mass and the empirical formula mass:

* Whole number ratio = (Molar mass) / (Empirical formula mass) = 30 g/mol / 15.04 g/mol ≈ 2

3. Multiply the subscripts in the empirical formula by the whole number ratio:

* Molecular formula = (CH3) * 2 = C2H6

Therefore, the molecular formula of the compound is C2H6 (ethane).