Here's the breakdown:
* Bromine water: This is a solution of bromine (Br2) in water. Bromine is a reddish-brown liquid that is moderately soluble in water.
* Sodium hydroxide: This is a strong base that can deprotonate various compounds.
* Hexane: This is an alkane, a non-polar hydrocarbon.
The reaction:
1. Formation of hypobromite ion: Sodium hydroxide reacts with bromine water to form hypobromite ion (BrO-), a powerful oxidizing agent. The reaction is as follows:
Br2 + 2NaOH → NaBr + NaBrO + H2O
2. Reaction with hexane: The hypobromite ion will react with hexane, specifically with the C-H bonds on the alkane, in a halogenation reaction. This reaction substitutes a hydrogen atom on the hexane molecule with a bromine atom, forming a brominated alkane.
C6H14 + BrO- → C6H13Br + OH-
Overall reaction:
The overall reaction can be summarized as:
C6H14 + Br2 + 2NaOH → C6H13Br + NaBr + NaBrO + H2O
Key points:
* The reaction is favored under alkaline conditions.
* The reaction is a substitution reaction where a bromine atom replaces a hydrogen atom on the hexane molecule.
* The reaction is relatively slow at room temperature.
* The product, a brominated alkane, is a colorless liquid that is denser than water.
Note: This reaction is a good example of how a seemingly simple reaction can be more complex than it appears. The key to understanding the reaction is to recognize that the bromine water is not the direct reactant, but rather a source of hypobromite ions, which are the actual oxidizing agent.