1. Balanced Chemical Equation:

The balanced chemical equation for the combustion of glucose (C6H12O6) is:

C6H12O6 + 6O2 → 6CO2 + 6H2O

2. Mole Ratios:

The equation shows that 1 mole of glucose (C6H12O6) reacts to produce 6 moles of carbon dioxide (CO2).

3. Convert Grams to Moles:

* Glucose:

* Molar mass of C6H12O6 = (6 * 12.01 g/mol) + (12 * 1.01 g/mol) + (6 * 16.00 g/mol) = 180.18 g/mol

* Moles of glucose = (45 g) / (180.18 g/mol) = 0.25 mol

4. Calculate Moles of Carbon Dioxide:

* Using the mole ratio from the balanced equation:

* Moles of CO2 = 0.25 mol glucose * (6 mol CO2 / 1 mol glucose) = 1.5 mol CO2

5. Convert Moles of Carbon Dioxide to Grams:

* Molar mass of CO2 = (12.01 g/mol) + (2 * 16.00 g/mol) = 44.01 g/mol

* Grams of CO2 = (1.5 mol) * (44.01 g/mol) = 66.02 g

Therefore, 66.02 grams of carbon dioxide would be produced if 45 grams of glucose completely reacted with oxygen.