1. Find the molar mass of KCl:
* Potassium (K): 39.10 g/mol
* Chlorine (Cl): 35.45 g/mol
* Molar mass of KCl: 39.10 + 35.45 = 74.55 g/mol
2. Calculate the moles of KCl:
* Moles = mass / molar mass
* Moles of KCl = 2.77 g / 74.55 g/mol = 0.0372 mol
3. Determine the moles of K:
* Since there is one K atom per KCl molecule, the moles of K are equal to the moles of KCl: 0.0372 mol
4. Convert moles of K to atoms of K:
* Avogadro's number: 6.022 x 10^23 atoms/mol
* Atoms of K = moles of K * Avogadro's number
* Atoms of K = 0.0372 mol * 6.022 x 10^23 atoms/mol = 2.24 x 10^22 atoms
Therefore, there are approximately 2.24 x 10^22 atoms of potassium in 2.77 g of KCl.
