Here's how to write the ionic equation for the reaction of silver nitrate (AgNO₃) and barium chloride (BaCl₂):

1. Write the balanced molecular equation:

2AgNO₃(aq) + BaCl₂(aq) → 2AgCl(s) + Ba(NO₃)₂(aq)

2. Identify the soluble and insoluble compounds:

* Soluble: AgNO₃, BaCl₂, Ba(NO₃)₂

* Insoluble: AgCl (This forms a precipitate)

3. Write the complete ionic equation:

2Ag⁺(aq) + 2NO₃⁻(aq) + Ba²⁺(aq) + 2Cl⁻(aq) → 2AgCl(s) + Ba²⁺(aq) + 2NO₃⁻(aq)

4. Cancel out spectator ions:

Spectator ions are those that appear on both sides of the equation and don't participate in the reaction. In this case, Ba²⁺ and NO₃⁻ are spectator ions.

5. Write the net ionic equation:

2Ag⁺(aq) + 2Cl⁻(aq) → 2AgCl(s)

Therefore, the net ionic equation for the reaction of silver nitrate and barium chloride is:

2Ag⁺(aq) + 2Cl⁻(aq) → 2AgCl(s)