The reaction between copper(II) sulfate (CuSO₄) and barium chloride (BaCl₂) is a double displacement reaction that results in the formation of two new compounds:

* Barium sulfate (BaSO₄), a white solid that is insoluble in water.

* Copper(II) chloride (CuCl₂), which remains dissolved in solution.

The balanced chemical equation for this reaction is:

CuSO₄(aq) + BaCl₂(aq) → BaSO₄(s) + CuCl₂(aq)

Here's a breakdown of what happens:

1. Mixing the reactants: When you mix solutions of copper(II) sulfate and barium chloride, the copper(II) ions (Cu²⁺) and sulfate ions (SO₄²⁻) from the first solution come into contact with the barium ions (Ba²⁺) and chloride ions (Cl⁻) from the second solution.

2. Double displacement: Due to electrostatic attraction, the copper(II) ions swap places with the barium ions.

3. Formation of precipitate: Barium sulfate (BaSO₄) is a very insoluble compound, meaning it doesn't dissolve well in water. As it forms, it precipitates out of the solution as a white solid.

4. Remaining solution: The copper(II) chloride (CuCl₂) formed is soluble in water and remains dissolved in the solution.

This reaction is a classic example of a precipitation reaction, where a solid product is formed and separates from the solution.