1. Write the Balanced Chemical Equation:

The reaction between sodium (Na) and oxygen (O₂) to form sodium oxide (Na₂O) is:

4 Na + O₂ → 2 Na₂O

2. Determine the Molar Mass of Each Substance:

* Na: 22.99 g/mol

* O₂: 32.00 g/mol (Oxygen is diatomic)

* Na₂O: 61.98 g/mol

3. Convert Grams of Sodium Oxide to Moles:

* Moles of Na₂O = (14.6 g Na₂O) / (61.98 g/mol Na₂O) = 0.235 mol Na₂O

4. Use the Mole Ratio from the Balanced Equation:

The balanced equation shows that 2 moles of Na₂O are produced from 1 mole of O₂. We can use this ratio to find the moles of O₂ needed:

* Moles of O₂ = (0.235 mol Na₂O) * (1 mol O₂ / 2 mol Na₂O) = 0.118 mol O₂

5. Convert Moles of Oxygen to Grams:

* Grams of O₂ = (0.118 mol O₂) * (32.00 g/mol O₂) = 3.78 g O₂

Therefore, 3.78 grams of oxygen gas are required to react completely with 14.6 grams of solid sodium to form oxide.