* We need the complete chemical reaction. The number of moles of silver chloride produced depends on the specific reaction involving nitrate. For example:

* Reaction 1: AgNO₃ (silver nitrate) + NaCl (sodium chloride) → AgCl (silver chloride) + NaNO₃ (sodium nitrate)

* Reaction 2: 2 AgNO₃ (silver nitrate) + CaCl₂ (calcium chloride) → 2 AgCl (silver chloride) + Ca(NO₃)₂ (calcium nitrate)

* We need to know the limiting reactant. The amount of product formed is determined by the reactant that runs out first.

Here's how to solve the problem once you have the complete reaction:

1. Balance the Chemical Equation: Make sure the number of atoms of each element is the same on both sides of the equation.

2. Identify the Mole Ratio: The balanced equation will show the ratio of moles of nitrate to moles of silver chloride produced.

3. Calculate Moles of Silver Chloride: Multiply the moles of nitrate by the mole ratio from step 2.

Example:

Let's use the first reaction above:

AgNO₃ + NaCl → AgCl + NaNO₃

1. Balanced: The equation is already balanced.

2. Mole Ratio: The ratio is 1 mole of AgNO₃ to 1 mole of AgCl.

3. Calculate Moles of AgCl: If you have 7 moles of AgNO₃, you will produce 7 moles of AgCl (since the ratio is 1:1).

Please provide the complete chemical reaction so I can give you a specific answer!