Here's what happens:
* Reactants: NaI (aq) + AgNO₃ (aq)
* Products: AgI (s) + NaNO₃ (aq)
Explanation:
1. Double displacement: The positively charged ions (cations) and negatively charged ions (anions) of the reactants switch partners. Sodium (Na⁺) from NaI combines with nitrate (NO₃⁻) from AgNO₃ to form sodium nitrate (NaNO₃). Silver (Ag⁺) from AgNO₃ combines with iodide (I⁻) from NaI to form silver iodide (AgI).
2. Precipitation: Silver iodide (AgI) is insoluble in water, meaning it doesn't dissolve readily. Therefore, it forms a solid precipitate, which appears as a yellow-white solid in the solution.
3. Net Ionic Equation: This reaction can be represented by a net ionic equation, which shows only the ions that participate in the precipitation:
Ag⁺ (aq) + I⁻ (aq) → AgI (s)
In Summary:
The reaction between sodium iodide and silver nitrate produces a yellow-white precipitate of silver iodide (AgI) and a solution of sodium nitrate (NaNO₃). This reaction is used in qualitative analysis to identify the presence of iodide ions.
