1. Convert grams of KCl to moles:
* Molar mass of KCl:
* K: 39.10 g/mol
* Cl: 35.45 g/mol
* Total: 39.10 + 35.45 = 74.55 g/mol
* Moles of KCl:
* (85.0 g KCl) / (74.55 g/mol KCl) = 1.14 mol KCl
2. Convert volume to liters:
* Volume in liters: (400.0 mL) / (1000 mL/L) = 0.400 L
3. Calculate molarity:
* Molarity (M) = moles of solute / liters of solution
* M = (1.14 mol KCl) / (0.400 L)
* M = 2.85 M
Therefore, the molarity of the potassium chloride solution is 2.85 M.