1. Calculate moles of NaOH:
* Molarity (M) = moles of solute / liters of solution
* We know:
* Molarity = 0.500 M
* Volume = 675 mL = 0.675 L
* Rearranging the formula to solve for moles:
* moles of NaOH = Molarity * Volume
* moles of NaOH = 0.500 M * 0.675 L = 0.3375 moles
2. Calculate mass of NaOH:
* Moles = mass / molar mass
* We know:
* moles of NaOH = 0.3375 moles
* Molar mass of NaOH = 40.00 g/mol (approximately)
* Rearranging the formula to solve for mass:
* mass of NaOH = moles * molar mass
* mass of NaOH = 0.3375 moles * 40.00 g/mol = 13.5 g
Therefore, there are approximately 13.5 grams of sodium hydroxide present in 675 mL of a 0.500 M solution.
