The compound formula for iron(III) sulfate is Fe₂(SO₄)₃. Here's how to break it down:

* Iron(III): This tells us the iron ion has a +3 charge (Fe³⁺).

* Sulfate: This is the polyatomic ion SO₄²⁻.

* Balancing charges: To create a neutral compound, we need two iron(III) ions (2 x +3 = +6) and three sulfate ions (3 x -2 = -6).

Therefore, the final formula is Fe₂(SO₄)₃.