* Identify the elements: Silver (Ag), Nitrogen (N), Oxygen (O)
* Find the atomic mass of each element:
* Silver (Ag): 107.87 g/mol
* Nitrogen (N): 14.01 g/mol
* Oxygen (O): 16.00 g/mol
* Multiply the atomic mass of each element by its subscript in the chemical formula:
* Ag: 107.87 g/mol * 1 = 107.87 g/mol
* N: 14.01 g/mol * 1 = 14.01 g/mol
* O: 16.00 g/mol * 3 = 48.00 g/mol
* Add the masses of all the elements together:
* 107.87 g/mol + 14.01 g/mol + 48.00 g/mol = 169.88 g/mol
Therefore, the molar mass of silver nitrate (AgNO₃) is 169.88 g/mol.
