1. Write the unbalanced equation:
Ba(OH)₂ (aq) + Na₂SO₄ (aq) → BaSO₄ (s) + NaOH (aq)
2. Identify the reactants and products:
* Reactants: Barium hydroxide (Ba(OH)₂) and sodium sulfate (Na₂SO₄)
* Products: Barium sulfate (BaSO₄) and sodium hydroxide (NaOH)
3. Balance the equation:
* Barium (Ba): Already balanced (1 on each side)
* Sulfur (S): Already balanced (1 on each side)
* Oxygen (O): 6 on the left, 6 on the right
* Hydrogen (H): 2 on the left, 1 on the right
* Sodium (Na): 2 on the left, 1 on the right
To balance the sodium and hydrogen, place a coefficient of 2 in front of NaOH:
Ba(OH)₂ (aq) + Na₂SO₄ (aq) → BaSO₄ (s) + 2 NaOH (aq)
4. The balanced equation:
Ba(OH)₂ (aq) + Na₂SO₄ (aq) → BaSO₄ (s) + 2 NaOH (aq)
