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  • Solubility of Substances in Carbon Tetrachloride (CCl4): A Detailed Explanation
    Here's how to determine which substances are soluble in carbon tetrachloride (CCl4):

    Understanding Solubility

    * "Like dissolves like": This principle states that polar solvents dissolve polar solutes, and nonpolar solvents dissolve nonpolar solutes.

    Analyzing the Substances

    * CCl4 (Carbon Tetrachloride): Nonpolar (symmetrical molecule with no significant dipole moment)

    * Br2 (Bromine): Nonpolar (diatomic molecule with no significant dipole moment)

    * C6H14 (Hexane): Nonpolar (hydrocarbon with only C-H bonds)

    * NaNO3 (Sodium Nitrate): Ionic compound, highly polar

    * HCl (Hydrogen Chloride): Polar covalent molecule (due to electronegativity difference between H and Cl)

    Solubility in CCl4

    Based on the "like dissolves like" principle:

    * Soluble:

    * CCl4: CCl4 will dissolve in itself (it's a nonpolar solvent).

    * Br2: Bromine is nonpolar and will dissolve in CCl4.

    * C6H14: Hexane is nonpolar and will dissolve in CCl4.

    * Insoluble:

    * NaNO3: Sodium nitrate is ionic and highly polar. It won't dissolve in the nonpolar CCl4.

    * HCl: Hydrogen chloride is polar and won't dissolve well in the nonpolar CCl4.

    Therefore, the following substances will be soluble in carbon tetrachloride (CCl4):

    * CCl4

    * Br2

    * C6H14

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