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  • Oxidation States of Elements in SO3²⁻: A Detailed Explanation
    Here's how to determine the oxidation states of sulfur (S) and oxygen (O) in the sulfite ion (SO₃⁻²):

    Rules to Remember:

    * Oxygen's oxidation state is typically -2, except in peroxides (where it's -1) and when bonded to fluorine (where it's positive).

    * The sum of the oxidation states in a polyatomic ion must equal the charge of the ion.

    Applying the Rules:

    1. Oxygen: We have three oxygen atoms, each with an oxidation state of -2. This contributes a total of 3 * (-2) = -6 to the overall charge.

    2. Sulfur: Since the sulfite ion (SO₃⁻²) has a charge of -2, and the oxygen atoms contribute -6, the sulfur atom must have an oxidation state of +4 to balance it out.

    Therefore, the oxidation states are:

    * Sulfur (S): +4

    * Oxygen (O): -2

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