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  • Copper Carbonate + Sulfuric Acid Reaction: Balanced Chemical Equation & Explanation
    The symbol equation for the reaction of copper carbonate with sulfuric acid is:

    CuCO₃(s) + H₂SO₄(aq) → CuSO₄(aq) + H₂O(l) + CO₂(g)

    Here's what each part of the equation represents:

    * CuCO₃(s): Copper carbonate (solid)

    * H₂SO₄(aq): Sulfuric acid (aqueous solution)

    * CuSO₄(aq): Copper sulfate (aqueous solution)

    * H₂O(l): Water (liquid)

    * CO₂(g): Carbon dioxide (gas)

    This reaction is a classic example of a double displacement reaction, where the positive and negative ions of the reactants switch places to form new products. In this case, the copper ions (Cu²⁺) from copper carbonate combine with the sulfate ions (SO₄²⁻) from sulfuric acid to form copper sulfate. The hydrogen ions (H⁺) from sulfuric acid combine with the carbonate ions (CO₃²⁻) from copper carbonate to form carbonic acid (H₂CO₃), which quickly decomposes into water and carbon dioxide.

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