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  • Calculating Calcium Mass Equivalent to Sulfur Atoms
    Here's how to solve this problem:

    1. Calculate the moles of sulfur:

    * Molar mass of sulfur (S) = 32.06 g/mol

    * Moles of sulfur = (mass of sulfur) / (molar mass of sulfur)

    * Moles of sulfur = 3.2 g / 32.06 g/mol = 0.1 mol

    2. Determine the number of atoms in 0.1 mol of sulfur:

    * Avogadro's number = 6.022 x 10^23 atoms/mol

    * Number of sulfur atoms = (moles of sulfur) * (Avogadro's number)

    * Number of sulfur atoms = 0.1 mol * 6.022 x 10^23 atoms/mol = 6.022 x 10^22 atoms

    3. Calculate the moles of calcium needed to have the same number of atoms:

    * Since we want the same number of atoms, the number of moles of calcium will be the same as the moles of sulfur (0.1 mol).

    4. Calculate the weight of calcium:

    * Molar mass of calcium (Ca) = 40.08 g/mol

    * Weight of calcium = (moles of calcium) * (molar mass of calcium)

    * Weight of calcium = 0.1 mol * 40.08 g/mol = 4.008 g

    Therefore, 4.008 grams of calcium contains the same number of atoms as 3.2 grams of sulfur.

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