1. Write the Balanced Chemical Equation:
The reaction for the formation of water is:
2H₂ + O₂ → 2H₂O
This means 2 moles of hydrogen (H₂) react with 1 mole of oxygen (O₂) to produce 2 moles of water (H₂O).
2. Calculate Moles of Oxygen:
* Find the molar mass of oxygen (O₂): 16 g/mol (O) * 2 = 32 g/mol (O₂)
* Divide the mass of oxygen by its molar mass: 22.1 g / 32 g/mol = 0.691 moles of O₂
3. Determine Moles of Water Produced:
* Use the mole ratio from the balanced equation: 1 mole O₂ produces 2 moles H₂O
* Multiply the moles of oxygen by the mole ratio: 0.691 moles O₂ * (2 moles H₂O / 1 mole O₂) = 1.382 moles H₂O
4. Calculate Grams of Water:
* Find the molar mass of water (H₂O): 1 g/mol (H) * 2 + 16 g/mol (O) = 18 g/mol (H₂O)
* Multiply the moles of water by its molar mass: 1.382 moles H₂O * 18 g/mol = 24.88 g H₂O
Therefore, approximately 24.88 grams of water are produced from 22.1 grams of oxygen.
