1. Write the Balanced Chemical Equation:

The balanced chemical equation for the combustion of glucose (C6H12O6) is:

C6H12O6 + 6O2 → 6CO2 + 6H2O

2. Determine the Molar Mass of Glucose and Carbon Dioxide:

* Glucose (C6H12O6): (6 * 12.01 g/mol) + (12 * 1.01 g/mol) + (6 * 16.00 g/mol) = 180.18 g/mol

* Carbon Dioxide (CO2): (12.01 g/mol) + (2 * 16.00 g/mol) = 44.01 g/mol

3. Calculate the Moles of Glucose:

* Moles of glucose = (mass of glucose) / (molar mass of glucose)

* Moles of glucose = (45 g) / (180.18 g/mol) = 0.25 mol

4. Use the Mole Ratio from the Balanced Equation:

The balanced equation shows that 1 mole of glucose produces 6 moles of carbon dioxide.

5. Calculate the Moles of Carbon Dioxide Produced:

* Moles of CO2 = (moles of glucose) * (6 moles CO2 / 1 mole glucose)

* Moles of CO2 = (0.25 mol) * (6) = 1.5 mol

6. Calculate the Mass of Carbon Dioxide:

* Mass of CO2 = (moles of CO2) * (molar mass of CO2)

* Mass of CO2 = (1.5 mol) * (44.01 g/mol) = 66.02 g

Therefore, 66.02 grams of carbon dioxide would be produced if 45 g of glucose completely reacted with oxygen.