Here's how to arrive at the formula:

* Lead(II) has a +2 charge (Pb²⁺).

* Phosphate is a polyatomic ion with a -3 charge (PO₄³⁻).

To balance the charges, we need three lead(II) ions (3 x +2 = +6) and two phosphate ions (2 x -3 = -6). This gives us the final formula: Pb₃(PO₄)₂.