1. Write the Balanced Chemical Equation
The reaction between copper (Cu) and oxygen (O₂) to form copper(II) oxide (CuO) is:
2 Cu + O₂ → 2 CuO
2. Calculate Moles of Reactants
* Moles of Copper:
- Molar mass of copper (Cu) = 63.55 g/mol
- Moles of Cu = 127 g / 63.55 g/mol = 2 moles
* Moles of Oxygen:
- Molar mass of oxygen (O₂) = 32 g/mol
- Moles of O₂ = 32 g / 32 g/mol = 1 mole
3. Determine the Limiting Reactant
The balanced equation tells us that 2 moles of Cu react with 1 mole of O₂. Since we have 2 moles of Cu and 1 mole of O₂, oxygen is the limiting reactant. This means that the amount of copper(II) oxide produced will be determined by how much oxygen is available.
4. Calculate Moles of Copper(II) Oxide Produced
From the balanced equation, we see that 1 mole of O₂ produces 2 moles of CuO.
* Moles of CuO = 1 mole O₂ * (2 moles CuO / 1 mole O₂) = 2 moles CuO
5. Calculate the Mass of Copper(II) Oxide Produced
* Molar mass of CuO = 63.55 g/mol (Cu) + 16.00 g/mol (O) = 79.55 g/mol
* Mass of CuO = 2 moles CuO * 79.55 g/mol = 159.1 g
Answer:
159.1 g of copper(II) oxide (CuO) will be produced.
