1. Convert mass to moles:

* Nitrogen (N): 4.12 g N * (1 mol N / 14.01 g N) = 0.294 mol N

* Hydrogen (H): 0.88 g H * (1 mol H / 1.01 g H) = 0.871 mol H

2. Find the mole ratio:

Divide each mole value by the smallest mole value (0.294 mol N):

* N: 0.294 mol / 0.294 mol = 1

* H: 0.871 mol / 0.294 mol ≈ 3

3. Write the empirical formula:

The empirical formula is NH₃.