1. The Reaction
Pentene, an alkene, has a double bond. Bromine, a diatomic molecule, is an electrophile (electron-seeking). When bromine approaches the double bond, it induces a polarization in the bromine molecule, making one bromine atom slightly positive (δ+) and the other slightly negative (δ-).
2. Mechanism
* Step 1: The slightly positive bromine atom attacks the electron-rich double bond of pentene, breaking the double bond and forming a carbocation intermediate.
* Step 2: The bromide ion (Br⁻) then attacks the carbocation, forming a new carbon-bromine bond.
3. Product
The product of the reaction is 2,3-dibromopentane.
Equation:
```
CH₃CH₂CH=CHCH₃ + Br₂ → CH₃CH₂CHBrCHBrCH₃
```
Important Note: The reaction is stereospecific, meaning the stereochemistry of the product depends on the stereochemistry of the starting alkene. If the pentene is cis, the product will be the cis-dibromopentane. If the pentene is trans, the product will be the trans-dibromopentane.
Let me know if you'd like to see a more detailed mechanism or have any other questions!