1. Identify the elements and their atomic masses:

* Aluminum (Al): 26.98 g/mol

* Chlorine (Cl): 35.45 g/mol

* Oxygen (O): 16.00 g/mol

2. Determine the number of atoms of each element in the formula:

* Aluminum (Al): 1 atom

* Chlorine (Cl): 3 atoms

* Oxygen (O): 9 atoms (3 oxygen atoms per chlorate ion, and 3 chlorate ions)

3. Calculate the total mass:

* Aluminum: 1 atom * 26.98 g/mol = 26.98 g/mol

* Chlorine: 3 atoms * 35.45 g/mol = 106.35 g/mol

* Oxygen: 9 atoms * 16.00 g/mol = 144.00 g/mol

4. Add up the masses of all the elements:

26.98 g/mol + 106.35 g/mol + 144.00 g/mol = 277.33 g/mol

Therefore, the molar mass of aluminum chlorate (Al(ClO₃)₃) is 277.33 g/mol.