1. Write the Balanced Chemical Equation:

The balanced chemical equation for the combustion of ethene (C2H4) is:

C2H4 + 3O2 → 2CO2 + 2H2O

2. Calculate the Moles of Ethene:

* Molar mass of C2H4: (2 * 12.01 g/mol) + (4 * 1.01 g/mol) = 28.05 g/mol

* Moles of C2H4: (50.0 g C2H4) / (28.05 g/mol) = 1.78 mol C2H4

3. Use the Mole Ratio to Find Moles of CO2:

* From the balanced equation, we see that 1 mole of C2H4 produces 2 moles of CO2.

* Moles of CO2: (1.78 mol C2H4) * (2 mol CO2 / 1 mol C2H4) = 3.56 mol CO2

4. Calculate the Mass of CO2:

* Molar mass of CO2: (12.01 g/mol) + (2 * 16.00 g/mol) = 44.01 g/mol

* Mass of CO2: (3.56 mol CO2) * (44.01 g/mol) = 156 g CO2

Therefore, 156 g of CO2 is produced when 50.0 g of C2H4 reacts completely.