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  • Stoichiometry Calculation: Moles of Cl⁻ for Mg²⁺ Combination
    Here's how to solve this problem:

    Understanding the Chemistry

    * Magnesium (Mg) forms a +2 ion (Mg²⁺).

    * Chlorine (Cl) forms a -1 ion (Cl⁻).

    Balancing the Charges

    To form a neutral compound, we need two chloride ions (Cl⁻) for every one magnesium ion (Mg²⁺). This is because:

    * 2 (Cl⁻) charges + 1 (Mg²⁺) charge = 0

    Calculating the Moles

    1. Mole Ratio: The mole ratio of Mg²⁺ to Cl⁻ is 1:2. This means for every 1 mole of Mg²⁺, we need 2 moles of Cl⁻.

    2. Calculation: Since we have 0.25 moles of Mg²⁺, we need:

    0.25 moles Mg²⁺ * (2 moles Cl⁻ / 1 mole Mg²⁺) = 0.50 moles Cl⁻

    Answer: You need 0.50 moles of Cl⁻ ions to completely combine with 0.25 moles of Mg²⁺ ions.

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