1. Find the atomic masses of each element:
* Sodium (Na): 22.99 u
* Oxygen (O): 16.00 u
* Hydrogen (H): 1.01 u
2. Multiply each atomic mass by its subscript in the formula:
* Na: 22.99 u * 1 = 22.99 u
* O: 16.00 u * 1 = 16.00 u
* H: 1.01 u * 1 = 1.01 u
3. Add the results together:
22.99 u + 16.00 u + 1.01 u = 40.00 u
Therefore, the relative formula mass of sodium hydroxide (NaOH) is 40.00 u.
