1. Understand the Reaction

Silver nitrate (AgNO₃) reacts with chloride ions (Cl⁻) to form a white precipitate of silver chloride (AgCl):

AgNO₃(aq) + Cl⁻(aq) → AgCl(s) + NO₃⁻(aq)

2. Calculate Moles of Chloride

* Molar mass of AgCl: 143.32 g/mol

* Moles of AgCl: (8.07 g AgCl) / (143.32 g/mol) = 0.0563 mol AgCl

Since the reaction is 1:1, the moles of chloride ions are equal to the moles of AgCl: 0.0563 mol Cl⁻

3. Calculate Chloride Concentration

* Volume of solution: 229 mL = 0.229 L

* Concentration of chloride ions: (0.0563 mol Cl⁻) / (0.229 L) = 0.246 M

Therefore, the concentration of chloride ions in the 229 mL solution is 0.246 M.