1. Write the balanced dissolution equation:
Ag₂CrO₄(s) ⇌ 2Ag⁺(aq) + CrO₄²⁻(aq)
2. Write the solubility product expression (Ksp):
Ksp = [Ag⁺]²[CrO₄²⁻]
Explanation:
* Ksp: The solubility product constant represents the equilibrium constant for the dissolution of a sparingly soluble ionic compound. It's a measure of the compound's solubility.
* [Ag⁺]²: The concentration of silver ions raised to the power of 2 because 2 moles of Ag⁺ are produced for every mole of Ag₂CrO₄ that dissolves.
* [CrO₄²⁻]: The concentration of chromate ions.
Therefore, the solubility product expression for silver chromate is Ksp = [Ag⁺]²[CrO₄²⁻].
