You can't directly calculate the electronegativity difference for AlBr3 because it's a molecule, not a bond. Electronegativity difference is a concept that applies to individual bonds between two atoms.

Here's why:

* Electronegativity: A measure of an atom's ability to attract electrons in a bond.

* Electronegativity Difference: The difference in electronegativity values between two atoms in a bond. This difference determines the type of bond (ionic, polar covalent, nonpolar covalent).

To find the electronegativity difference, you'd need to consider the individual Al-Br bonds within the AlBr3 molecule.

Here's how you'd do that:

1. Look up electronegativity values: You can find these values in a periodic table or a chemistry textbook.

* Aluminum (Al): 1.61

* Bromine (Br): 2.96

2. Calculate the difference: 2.96 - 1.61 = 1.35

3. Interpret the difference: A difference of 1.35 indicates a polar covalent bond between Al and Br. This means that the electrons in the bond are not shared equally, with the Br atom having a slightly stronger pull on the electrons.

Therefore, the electronegativity difference in each Al-Br bond of AlBr3 is 1.35.