The balanced reaction between sodium hydroxide (NaOH) and copper bromide (CuBr₂) is:

2 NaOH + CuBr₂ → Cu(OH)₂ + 2 NaBr

Here's a breakdown of the reaction:

* Reactants:

* Sodium hydroxide (NaOH) is a strong base.

* Copper bromide (CuBr₂) is a soluble ionic compound.

* Products:

* Copper(II) hydroxide (Cu(OH)₂) is a blue-green precipitate that forms.

* Sodium bromide (NaBr) is a soluble ionic compound that remains in solution.

The reaction is a double displacement reaction. This means that the positive and negative ions of the reactants switch places to form the products.

Here's how to balance the reaction:

1. Start with the unbalanced equation: NaOH + CuBr₂ → Cu(OH)₂ + NaBr

2. Count the number of atoms of each element on both sides:

* Na: 1 on the left, 1 on the right

* O: 1 on the left, 2 on the right

* H: 1 on the left, 2 on the right

* Cu: 1 on the left, 1 on the right

* Br: 2 on the left, 1 on the right

3. Adjust the coefficients in front of each compound to balance the number of atoms:

* Place a "2" in front of NaOH and NaBr to balance the Na, O, H, and Br atoms.

The balanced equation is 2 NaOH + CuBr₂ → Cu(OH)₂ + 2 NaBr