Here's how to write the balanced equation for the reaction between calcium chloride (CaCl₂) and lead(II) acetate (Pb(CH₃COO)₂):

1. Write the unbalanced equation:

CaCl₂ (aq) + Pb(CH₃COO)₂ (aq) → Ca(CH₃COO)₂ (aq) + PbCl₂ (s)

2. Balance the equation:

* Lead (Pb): Already balanced (1 on each side).

* Calcium (Ca): Already balanced (1 on each side).

* Chlorine (Cl): 2 on the left, 2 on the right.

* Carbon (C): 4 on the right, 4 on the left.

* Oxygen (O): 4 on the right, 4 on the left.

* Hydrogen (H): 6 on the right, 6 on the left.

The balanced equation is:

CaCl₂ (aq) + Pb(CH₃COO)₂ (aq) → Ca(CH₃COO)₂ (aq) + PbCl₂ (s)