2 C₄H₁₀ + 13 O₂ → 8 CO₂ + 10 H₂O
Explanation:
* Reactants:
* Butane (C₄H₁₀): A hydrocarbon fuel.
* Oxygen (O₂): The oxidizer needed for combustion.
* Products:
* Carbon dioxide (CO₂): A product of complete combustion.
* Water (H₂O): Another product of complete combustion.
Balancing the equation:
* Carbon (C): There are 4 carbon atoms on the left side (in C₄H₁₀) and 8 on the right side (in CO₂). To balance this, we need a coefficient of 2 in front of C₄H₁₀.
* Hydrogen (H): There are 10 hydrogen atoms on the left side (in C₄H₁₀) and 10 on the right side (in H₂O). This is already balanced.
* Oxygen (O): There are 2 oxygen atoms on the left side (in O₂) and 26 on the right side (in CO₂ and H₂O). To balance this, we need a coefficient of 13 in front of O₂.
By adjusting the coefficients, the number of each type of atom on both sides of the equation is now equal.