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  • Potassium and Bromine Reaction: Understanding KBr Formation
    When a potassium atom reacts with bromine, it will form potassium bromide (KBr). Here's why:

    * Potassium (K) is a metal in Group 1 of the periodic table. It has one valence electron (electron in its outermost shell).

    * Bromine (Br) is a nonmetal in Group 17 of the periodic table. It has seven valence electrons.

    The reaction:

    Potassium readily loses its single valence electron to achieve a stable noble gas configuration. Bromine gains one electron to also achieve a stable noble gas configuration. This results in an ionic bond:

    * Potassium loses an electron and becomes a positively charged ion (K+).

    * Bromine gains an electron and becomes a negatively charged ion (Br-).

    These oppositely charged ions attract each other, forming the ionic compound potassium bromide (KBr).

    The chemical equation:

    2K + Br₂ → 2KBr

    This equation shows that two potassium atoms react with one bromine molecule (Br₂) to produce two formula units of potassium bromide.

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