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  • Barium and Oxygen Reaction: Electron Loss and Ionic Formation
    Yes, that's correct! Here's why:

    * Barium (Ba) is an alkaline earth metal, located in Group 2 of the periodic table. This means it has two valence electrons (electrons in its outermost shell).

    * Oxygen (O) is a nonmetal in Group 16, meaning it has six valence electrons. It needs two more electrons to achieve a stable octet (8 electrons in its outer shell).

    The Reaction:

    When barium and oxygen react, barium loses its two valence electrons to become a positively charged ion (cation):

    * Ba → Ba²⁺ + 2e⁻

    Oxygen gains these two electrons, becoming a negatively charged ion (anion):

    * O + 2e⁻ → O²⁻

    The resulting ions, Ba²⁺ and O²⁻, have opposite charges and attract each other electrostatically, forming the ionic compound barium oxide (BaO).

    Key takeaway: Barium loses two electrons to form a +2 cation, while oxygen gains two electrons to form a -2 anion. This is a classic example of ionic bonding.

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