Here's how to write the balanced reaction for lead(II) nitrate and calcium chloride:

1. Identify the Reactants:

* Lead(II) nitrate: Pb(NO₃)₂

* Calcium chloride: CaCl₂

2. Identify the Products:

* Lead(II) chloride: PbCl₂ (This is a white precipitate that forms)

* Calcium nitrate: Ca(NO₃)₂ (This remains in solution)

3. Write the Unbalanced Equation:

Pb(NO₃)₂ (aq) + CaCl₂ (aq) → PbCl₂ (s) + Ca(NO₃)₂ (aq)

4. Balance the Equation:

* Lead (Pb): Already balanced (1 on each side)

* Nitrate (NO₃): 2 on the left, 2 on the right (balanced)

* Calcium (Ca): 1 on each side (balanced)

* Chloride (Cl): 2 on the left, 2 on the right (balanced)

The balanced chemical equation is:

Pb(NO₃)₂ (aq) + CaCl₂ (aq) → PbCl₂ (s) + Ca(NO₃)₂ (aq)