1. Write the Balanced Chemical Equation:

Fe(s) + Cl₂(g) → FeCl₂(s)

2. Calculate the Moles of Iron:

* Molar mass of iron (Fe) = 55.845 g/mol

* Moles of Fe = (6.0 g) / (55.845 g/mol) = 0.107 mol

3. Determine the Mole Ratio:

* From the balanced equation, 1 mole of Fe reacts to produce 1 mole of FeCl₂.

4. Calculate the Maximum Moles of Iron-II Chloride (FeCl₂):

* Since the mole ratio is 1:1, the maximum moles of FeCl₂ produced is equal to the moles of Fe: 0.107 mol FeCl₂

Answer: The maximum number of moles of iron-II chloride (FeCl₂) that can be produced is 0.107 mol.