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  • Calculating Molecules: How Many Are in 720g of Glucose (C6H12O6)?
    Here's how to calculate the number of molecules in 720 grams of C6H12O6 (glucose):

    1. Find the molar mass of glucose (C6H12O6):

    * Carbon (C): 6 atoms * 12.01 g/mol = 72.06 g/mol

    * Hydrogen (H): 12 atoms * 1.01 g/mol = 12.12 g/mol

    * Oxygen (O): 6 atoms * 16.00 g/mol = 96.00 g/mol

    * Total molar mass: 72.06 + 12.12 + 96.00 = 180.18 g/mol

    2. Convert grams of glucose to moles:

    * Moles = (mass in grams) / (molar mass)

    * Moles = 720 g / 180.18 g/mol = 4 moles

    3. Use Avogadro's number to find the number of molecules:

    * Avogadro's number: 6.022 x 10^23 molecules/mol

    * Number of molecules = (moles) * (Avogadro's number)

    * Number of molecules = 4 moles * 6.022 x 10^23 molecules/mol = 2.409 x 10^24 molecules

    Therefore, there are approximately 2.409 x 10^24 molecules in 720 grams of glucose.

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