1. Find the empirical formula mass:
* C: 12.01 g/mol
* H: 1.01 g/mol
* Empirical formula mass of CH2 = 12.01 + (1.01 x 2) = 14.03 g/mol
2. Determine the ratio of molecular mass to empirical formula mass:
* Molecular mass / Empirical formula mass = 84 g/mol / 14.03 g/mol ≈ 6
3. Multiply the subscripts in the empirical formula by the ratio:
* CH2 x 6 = C6H12
Therefore, the molecular formula of the compound is C6H12.