1. Write the balanced chemical equation:

C₃H₈O₃ + 4 O₂ → 3 CO₂ + 4 H₂O

This equation tells us that for every mole of C₃H₈O₃ that burns, 3 moles of CO₂ are produced.

2. Calculate the molar mass of C₃H₈O₃:

* C: 12.01 g/mol * 3 = 36.03 g/mol

* H: 1.01 g/mol * 8 = 8.08 g/mol

* O: 16.00 g/mol * 3 = 48.00 g/mol

* Total Molar Mass: 36.03 + 8.08 + 48.00 = 92.11 g/mol

3. Convert grams of C₃H₈O₃ to moles:

* Moles = grams / molar mass

* Moles = 23.0 g / 92.11 g/mol = 0.250 mol C₃H₈O₃

4. Use the mole ratio from the balanced equation to find moles of CO₂:

* From the equation: 1 mol C₃H₈O₃ produces 3 mol CO₂

* Moles CO₂ = 0.250 mol C₃H₈O₃ * (3 mol CO₂ / 1 mol C₃H₈O₃) = 0.750 mol CO₂

Therefore, 0.750 moles of carbon dioxide are produced when 23.0 g of C₃H₈O₃ burns.