1. Write the balanced chemical equation:

N₂ (g) + 3 H₂ (g) → 2 NH₃ (g)

2. Determine the limiting reactant:

* Nitrogen (N₂): You have 2 moles of nitrogen.

* Hydrogen (H₂): You have 6 moles of hydrogen.

The balanced equation shows that 1 mole of nitrogen reacts with 3 moles of hydrogen. Since you have 6 moles of hydrogen, you have enough to react completely with the 2 moles of nitrogen. Therefore, nitrogen is the limiting reactant.

3. Calculate the moles of ammonia produced:

The balanced equation shows that 1 mole of nitrogen produces 2 moles of ammonia. Since you have 2 moles of nitrogen, you'll produce:

2 moles N₂ * (2 moles NH₃ / 1 mole N₂) = 4 moles NH₃

4. Convert moles of ammonia to molecules:

To convert from moles to molecules, use Avogadro's number (6.022 x 10²³ molecules/mole):

4 moles NH₃ * (6.022 x 10²³ molecules/mole) = 2.409 x 10²⁴ molecules of ammonia

Therefore, 2.409 x 10²⁴ molecules of ammonia can be formed from the reaction.