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  • Calculating Iron Required for Sulfur Reaction: A Step-by-Step Guide
    Here's how to solve this problem:

    1. Balanced Chemical Equation:

    The balanced chemical equation is:

    2Fe + 3S → Fe₂S₃

    2. Convert Grams of Sulfur to Moles:

    * Find the molar mass of sulfur (S): 32.06 g/mol

    * Divide the mass of sulfur by its molar mass:

    48.0 g S / 32.06 g/mol = 1.497 mol S

    3. Use Mole Ratio from the Balanced Equation:

    * The balanced equation shows a 2:3 mole ratio between Fe and S.

    * For every 3 moles of S, we need 2 moles of Fe.

    * Calculate the moles of Fe needed: (1.497 mol S) * (2 mol Fe / 3 mol S) = 0.998 mol Fe

    4. Convert Moles of Iron to Grams:

    * Find the molar mass of iron (Fe): 55.845 g/mol

    * Multiply the moles of Fe by its molar mass:

    (0.998 mol Fe) * (55.845 g/mol) = 55.7 g Fe

    Answer: You need approximately 55.7 grams of iron to react completely with 48.0 grams of sulfur.

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