1. Identify the reactants:
* Potassium chloride (KCl)
* Silver acetate (AgC₂H₃O₂)
2. Understand double-replacement reactions:
In a double-replacement reaction, the positive and negative ions of two reactants switch partners. This can be represented as:
AB + CD → AD + CB
3. Apply the rule to our reactants:
* KCl --> K⁺ + Cl⁻
* AgC₂H₃O₂ --> Ag⁺ + C₂H₃O₂⁻
4. Switch the partners:
* K⁺ combines with C₂H₃O₂⁻ to form potassium acetate (KC₂H₃O₂)
* Ag⁺ combines with Cl⁻ to form silver chloride (AgCl)
5. Write the balanced chemical equation:
KCl(aq) + AgC₂H₃O₂(aq) → KC₂H₃O₂(aq) + AgCl(s)
Important Note: Silver chloride (AgCl) is insoluble in water, so it forms a precipitate (a solid that settles out of solution).
Therefore, the products of the double-replacement reaction between potassium chloride and silver acetate are potassium acetate (KC₂H₃O₂) and silver chloride (AgCl).
