Here's how to write the complete ionic equation for the reaction between sodium carbonate (Na₂CO₃) and lead(II) nitrate (Pb(NO₃)₂):

1. Write the balanced molecular equation:

Na₂CO₃(aq) + Pb(NO₃)₂(aq) → PbCO₃(s) + 2NaNO₃(aq)

2. Identify the soluble ionic compounds:

* Sodium carbonate (Na₂CO₃) - soluble in water

* Lead(II) nitrate (Pb(NO₃)₂) - soluble in water

* Lead(II) carbonate (PbCO₃) - insoluble in water (precipitate)

* Sodium nitrate (NaNO₃) - soluble in water

3. Write the complete ionic equation by breaking down soluble ionic compounds into their respective ions:

2Na⁺(aq) + CO₃²⁻(aq) + Pb²⁺(aq) + 2NO₃⁻(aq) → PbCO₃(s) + 2Na⁺(aq) + 2NO₃⁻(aq)

4. The complete ionic equation is:

2Na⁺(aq) + CO₃²⁻(aq) + Pb²⁺(aq) + 2NO₃⁻(aq) → PbCO₃(s) + 2Na⁺(aq) + 2NO₃⁻(aq)