1. Balanced Chemical Equation:

The reaction between sodium metal (Na) and water (H₂O) produces sodium hydroxide (NaOH) and hydrogen gas (H₂):

2 Na + 2 H₂O → 2 NaOH + H₂

2. Mole Ratio:

From the balanced equation, we see that:

* 2 moles of sodium (Na) react to produce 1 mole of hydrogen gas (H₂)

3. Calculation:

We are given 0.068 moles of sodium. To find the moles of hydrogen produced, we can set up a proportion:

(2 moles Na) / (1 mole H₂) = (0.068 moles Na) / (x moles H₂)

Solving for x:

x = (0.068 moles Na * 1 mole H₂) / 2 moles Na

x = 0.034 moles H₂

Therefore, theoretically, 0.034 moles of hydrogen gas should be produced when 0.068 moles of sodium metal reacts.