* The reaction: We need to know the complete chemical reaction involving barium chloride. For example:
* Reaction 1: BaCl₂ (aq) + Na₂SO₄ (aq) → BaSO₄ (s) + 2 NaCl (aq)
* Reaction 2: BaCl₂ (aq) + H₂SO₄ (aq) → BaSO₄ (s) + 2 HCl (aq)
* The limiting reactant: If we know the reaction, we also need to know the amount of the other reactant (like sodium sulfate or sulfuric acid) to determine the limiting reactant. The limiting reactant determines how much product can be formed.
Here's how to solve the problem once you have the complete information:
1. Balance the chemical equation: Make sure the number of atoms of each element is the same on both sides of the equation.
2. Identify the mole ratio: The balanced equation will show the ratio of moles of barium chloride to moles of barium sulfate.
3. Calculate moles of barium sulfate: Using the mole ratio from step 2 and the given moles of barium chloride, calculate the moles of barium sulfate produced.
Example using Reaction 1:
1. Balanced equation: BaCl₂ (aq) + Na₂SO₄ (aq) → BaSO₄ (s) + 2 NaCl (aq)
2. Mole ratio: The equation shows 1 mole of BaCl₂ produces 1 mole of BaSO₄.
3. Moles of BaSO₄: Since the ratio is 1:1, 0.100 moles of BaCl₂ will produce 0.100 moles of BaSO₄.
