1. Understanding the Formula:
* TiCl₃ indicates that each formula unit of titanium(III) chloride contains one titanium ion (Ti³⁺) and three chloride ions (Cl⁻).
2. Moles to Ions:
* Avogadro's number: 6.022 x 10²³ is the number of particles (atoms, molecules, ions, etc.) in one mole of a substance.
* Since there are 3 Cl⁻ ions per TiCl₃ formula unit, 0.5 mol of TiCl₃ will contain: 0.5 mol TiCl₃ * 3 Cl⁻ ions/TiCl₃ = 1.5 mol Cl⁻ ions
3. Calculate the Number of Ions:
* Number of Cl⁻ ions: 1.5 mol Cl⁻ * (6.022 x 10²³ Cl⁻ ions/mol Cl⁻) = 9.033 x 10²³ Cl⁻ ions
Therefore, there are approximately 9.033 x 10²³ chloride ions in 0.5 mol of titanium(III) chloride.
